Use Python Selenium to get span text

Question

This should be easy, but I can't get it to work. I'm running a little demo using the Google homepage as a test.

Here's my script:

from selenium import webdriver from selenium.common.exceptions import NoSuchElementException from selenium.webdriver.common.keys import Keys import time  browser = webdriver.Chrome() browser.get("http://www.google.com") # Load page  time.sleep(0.2)  #top nav elements elems = browser.find_elements_by_xpath("//span[contains(@class, 'gbts')]")   for e in elems:     print e.get_attribute('text')  browser.close() 

It returns:

None None None None None None None None None None None 

So I think it's grabbing the right elements, but perhaps not the right attribute? Not sure. I also tried to print e.text() but that spit out:

Traceback (most recent call last):   File "sample.py", line 14, in <module>     print e.text() TypeError: 'unicode' object is not callable 

Any thoughts?

*Edit - Possible Solution? *

e.get_attribute('innerHTML') seems to work. 

Answer 1

This should do it:

from selenium import webdriver browser = webdriver.Firefox() browser.get("http://www.google.com") for elem in browser.find_elements_by_xpath('.//span[@class = "gbts"]'):     print elem.text 

---

text is a property of the WebElement class, thus it is not callable.

class WebElement(object):     """Represents an HTML element.            ...     ...      @property     def text(self):         """Gets the text of the element."""         return self._execute(Command.GET_ELEMENT_TEXT)['value'] 

---

You have two alternatives to get the third match:

#  1. Modify your xpath expression browser.find_elements_by_xpath('(.//span[@class = "gbts"])[3]')[0].text  #  2. Access it by list index browser.find_elements_by_xpath('.//span[@class = "gbts"])')[2].text