Use loc and iloc together in pandas

Question

Say I have the following dataframe, and I want to change the two elements in column c that correspond to the first two elements in column a that are equal to 1 to equal 2.

>>> df = pd.DataFrame({"a" : [1,1,1,1,2,2,2,2], "b" : [2,3,1,4,5,6,7,2], "c" : [1,2,3,4,5,6,7,8]})
>>> df.loc[df["a"] == 1, "c"].iloc[0:2] = 2
>>> df
   a  b  c
0  1  2  1
1  1  3  2
2  1  1  3
3  1  4  4
4  2  5  5
5  2  6  6
6  2  7  7
7  2  2  8

The code in the second line doesn't work because iloc sets a copy, so the original dataframe is not modified. How would I do this?

Answer 1

A dirty way would be:

df.loc[df[df['a'] == 1][:2].index, 'c'] = 2