use "global-namespace";

Question

I just wonder if there's a way to make a class behave as if it is in global namespace using a "use" keyword, so this class would behave as namespaced class only from outside of the class. Something like:

namespace wherever\somewhere\deep\deep\inside;
use \; // root namespace.. note: this doesn't work
class stuff{
//....
}

anyone?

Answer 1

Using the global namespace won't work the way you expect.

By default, you can reference a globally namespaced class by adding a backslash -- eg $x = new \PDO(...);. Trying to use \ won't change that.

If you want to drop the backslash from globally namespaced classes, you need to use each of them specifically. In namespaced PHP, any class reference that doesn't have a namespace is assumed to be in the current namespace, unless it is explicitly referenced by a use statement.

eg:

use \PDO, \SplFileObject;

now we can call new PDO(...) or new SplFileObject() without the backslash. But other global classes that aren't in the use would still need the backslash.

Answer 2

You can access the global namespace if you use brackets like this:

namespace My\Space {
    function myScopedFunction() { .. }
}
namespace {
    function myGlobalFunction() { .. }
}