Use ends with in XSLT v1.0

Question

I am trying to edit a current XSLT. The functionality I want is when the value of "//code_no" ends with 01 I want to edit the current city location. Currently this functionality does not exist. I have tried using string and substring but it gives me an error saying ends with functionality does not exist. Please help

The value coming from the xml is

<code_no> 1870410001 </code_no> 

in the xsl, I want to print this when the value ends with 01.

<td align="left" width="33%"><SPAN style="font-size: 12pt; font-family: Arial;">     <a> <b><u><xsl:value-of select="//city"/>, <xsl:value-of select="//state"/>      </u></b></a></SPAN></td> 

Answer 1

The XPath 1.0 equivalent of (the XPath 2.0) expression:

ends-with($s, $t) 

is:

$t = substring($s, string-length($s) - string-length($t) +1) 

You need just to substitute $s and $t in the last XPath expression with, respectively, the string to be tested, and the ending to be tested.

Here is a complete example:

<xsl:stylesheet version="1.0"  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">  <xsl:output omit-xml-declaration="yes" indent="yes"/>  <xsl:strip-space elements="*"/>   <xsl:template match="x|y">      <xsl:value-of select="name()"/> ends-with '_01': <xsl:value-of select=      "'_01' = substring(., string-length() - 2)"/> =============     </xsl:template> </xsl:stylesheet> 

when this transformation is applied on the following XML document (none was provided in the question!!!):

<t>  <x>abcd_01</x>  <y>abcd_11</y> </t> 

the wanted, correct result is produced:

x ends-with '_01': true =============     y ends-with '_01': false =============    

Answer 2

I used

contains($string, $part) and normalize-space(substring-after($string, $part)) = '' 

Where

we are checking if $string ends with $part