Why is this complaining about a miss-type? map
supposed to transfor the value of an observable to another, but it's expecting me to return an observable from the map
override fun fetchExercises(): Observable<List<Exercise>> {
return FirebaseDatabase.getInstance()
.getReference("exercises")
.observeSingleEvent()
.map { snapshot: DataSnapshot? -> object: List<Exercise>
// Error here
return listOf<Exercise>()
}
}
fun DatabaseReference.observeSingleEvent(): Observable<DataSnapshot> {
return Observable.create(object : Observable.OnSubscribe<DataSnapshot> {
override fun call(subscriber: Subscriber<in DataSnapshot>) {
val valueEventListener = object: ValueEventListener {
override fun onDataChange(snapshot: DataSnapshot?) {
subscriber.onNext(snapshot)
subscriber.onCompleted()
}
override fun onCancelled(error: DatabaseError?) {
subscriber.onError(FirebaseDatabaseThrowable(error))
}
}
addListenerForSingleValueEvent(valueEventListener)
}
})
}
@zsmb13 has pointed out the correct answer right there. Here, I would like to comment on some mistake made in your lambda expression.
.map { snapshot: DataSnapshot? -> object: List<Exercise>
// Error here
return listOf<Exercise>()
}
object: List<Exercise>
here is not a valid syntax since the body goes after an ->
sign inside the lambda expression. We do not specify the return type inside the body.
Also, the return
here means to return from fetchExercises()
as described in Kotlin docs:
A return statement without a label always returns from the function declared with the fun keyword. This means that a return inside a lambda expression will return from the enclosing function, whereas a return inside an anonymous function will return from the anonymous function itself.
As what @zsmb13 said, return
is not needed in most of the case. If you really want it(for flow control), you can use qualified returns:
//This is answer from @zsmb13
.map { snapshot: DataSnapshot? ->
return@map listOf<Exercise>()
}
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