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URL Encode and Decode Special character in Java

Tags:

java

urlencode

In Java, I need to use HTTP Post to send request to server, but if in the parameter of the URL contains some special character it throws below Exception

java.lang.IllegalArgumentException: URLDecoder: Illegal hex characters in escape (%) pattern - For input string: "&'"

The code to send data

DefaultHttpClient httpclient = new DefaultHttpClient(); 
   HttpPost httpPost = new HttpPost(URL); 

   String sessionId = RequestUtil.getRequest().getSession().getId();
   String data = arg.getData().toString();

   List<NameValuePair> params = new ArrayList<NameValuePair>();   
   params.add(new BasicNameValuePair(param1, data));
   params.add(new BasicNameValuePair(param2, sessionId));
         httpPost.setEntity(new UrlEncodedFormEntity(params, "UTF-8"));           

   HttpResponse response = (HttpResponse) httpclient.execute(httpPost);

And at the server side, i use the below code to read information

 String data = request.getParameter(param1);
   if (data != null) {
    actionArg = new ChannelArg(URLDecoder.decode(data, "UTF-8"));
   }

The code works correctly but if i input some special character like [aああ#$%&'(<>?/.,あああああ], it will throw exception. I wonder if someone could help me some hint to be able to encode and decode special characters?

Thank you very much in advance.

like image 573
Phu Nguyen Avatar asked Jan 30 '11 05:01

Phu Nguyen


1 Answers

To encode text for safe passage through the internets:

import java.net.*;
...
try {
    encodedValue= URLEncoder.encode(rawValue, "UTF-8");
} catch (UnsupportedEncodingException uee) { }

And to decode:

try {
    decodedValue = URLDecoder.decode(rawValue, "UTF-8");
} catch (UnsupportedEncodingException uee) { }
like image 69
Steven Avatar answered Sep 18 '22 15:09

Steven