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URI scheme is not "file"

I get the exception: "URI scheme is not file"

What I am doing is trying to get the name of a file and then save that file (from another server) onto my computer/server from within a servlet.

I have a String called "url", from thereon here is my code:

url = Streams.asString(stream); //gets the URL from a form on a webpage
System.out.println("This is the URL: "+url);
URI fileUri = new URI(url);

File fileFromUri = new File(fileUri);                   

onlyFile = fileFromUri.getName(); 
URL fileUrl = new URL(url);
InputStream imageStream = fileUrl.openStream();
String fileLoc2 = getServletContext().getRealPath("pics/"+onlyFile);

File newFolder = new File(getServletContext().getRealPath("pics"));
    if(!newFolder.exists()){
        newFolder.mkdir();
    }
    IOUtils.copy(imageStream, new FileOutputStream("pics/"+onlyFile));
} 

The line causing the error is this one:

File fileFromUri = new File(fileUri);                   

I have added the rest of the code so you can see what I am trying to do.

like image 414
Ankur Avatar asked May 16 '10 11:05

Ankur


2 Answers

The URI "scheme" is the thing that comes before the ":", for example "http" in "http://stackoverflow.com".

The error message is telling you that new File(fileUri) works only on "file:" URI's (ones referring to a pathname on the current system), not other schemes like "http".

Basically, the "file:" URI is another way of specifying a pathname to the File class. It is not a magic way of telling File to use http to fetch a file from the web.

like image 89
David Gelhar Avatar answered Oct 30 '22 07:10

David Gelhar


Your assumption to create File from URL is wrong here.

You just don't need to create a File from URL to the file in the Internet, so that you get the file name.

You can simply do this with parsing the URL like that:

URL fileUri = new URL("http://local.wasp.uwa.edu.au/~pbourke/miscellaneous/domefisheye/ladybug/fish4.jpg");    
int startIndex = fileUri.toString().lastIndexOf('/');
String fileName = fileUri.toString().substring(startIndex + 1);
System.out.println(fileName);
like image 43
Leni Kirilov Avatar answered Oct 30 '22 05:10

Leni Kirilov