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Upload video from Android to server?

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Anyone suggest some sample to upload a video from the SD card to a remote server?

like image 433
Karthi Avatar asked Feb 16 '11 13:02

Karthi


2 Answers

Had the same issue some time ago. Here's a code.

public static int upLoad2Server(String sourceFileUri) {
  String upLoadServerUri = "your remote server link";
  // String [] string = sourceFileUri;
  String fileName = sourceFileUri;

  HttpURLConnection conn = null;
  DataOutputStream dos = null;
  DataInputStream inStream = null;
  String lineEnd = "\r\n";
  String twoHyphens = "--";
  String boundary = "*****";
  int bytesRead, bytesAvailable, bufferSize;
  byte[] buffer;
  int maxBufferSize = 1 * 1024 * 1024;
  String responseFromServer = "";

  File sourceFile = new File(sourceFileUri);
  if (!sourceFile.isFile()) {
   Log.e("Huzza", "Source File Does not exist");
   return 0;
  }
  try { // open a URL connection to the Servlet
   FileInputStream fileInputStream = new FileInputStream(sourceFile);
   URL url = new URL(upLoadServerUri);
   conn = (HttpURLConnection) url.openConnection(); // Open a HTTP  connection to  the URL
   conn.setDoInput(true); // Allow Inputs
   conn.setDoOutput(true); // Allow Outputs
   conn.setUseCaches(false); // Don't use a Cached Copy
   conn.setRequestMethod("POST");
   conn.setRequestProperty("Connection", "Keep-Alive");
   conn.setRequestProperty("ENCTYPE", "multipart/form-data");
   conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
   conn.setRequestProperty("uploaded_file", fileName);
   dos = new DataOutputStream(conn.getOutputStream());

   dos.writeBytes(twoHyphens + boundary + lineEnd);
   dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""+ fileName + "\"" + lineEnd);
   dos.writeBytes(lineEnd);

   bytesAvailable = fileInputStream.available(); // create a buffer of  maximum size
   Log.i("Huzza", "Initial .available : " + bytesAvailable);

   bufferSize = Math.min(bytesAvailable, maxBufferSize);
   buffer = new byte[bufferSize];

   // read file and write it into form...
   bytesRead = fileInputStream.read(buffer, 0, bufferSize);

   while (bytesRead > 0) {
    dos.write(buffer, 0, bufferSize);
     bytesAvailable = fileInputStream.available();
     bufferSize = Math.min(bytesAvailable, maxBufferSize);
    bytesRead = fileInputStream.read(buffer, 0, bufferSize);
    }

   // send multipart form data necesssary after file data...
   dos.writeBytes(lineEnd);
   dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

   // Responses from the server (code and message)
   serverResponseCode = conn.getResponseCode();
   String serverResponseMessage = conn.getResponseMessage();

   Log.i("Upload file to server", "HTTP Response is : " + serverResponseMessage + ": " + serverResponseCode);
   // close streams
   Log.i("Upload file to server", fileName + " File is written");
   fileInputStream.close();
   dos.flush();
   dos.close();
  } catch (MalformedURLException ex) {
   ex.printStackTrace();
   Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
  } catch (Exception e) {
   e.printStackTrace();
  }
//this block will give the response of upload link
  try {
   BufferedReader rd = new BufferedReader(new InputStreamReader(conn
     .getInputStream()));
   String line;
   while ((line = rd.readLine()) != null) {
    Log.i("Huzza", "RES Message: " + line);
   }
   rd.close();
  } catch (IOException ioex) {
   Log.e("Huzza", "error: " + ioex.getMessage(), ioex);
  }
  return serverResponseCode;  // like 200 (Ok)

 } // end upLoad2Server

2)call it with

int reponse=upLoad2Server(""+filepath);
like image 100
Vivienne Fosh Avatar answered Sep 20 '22 14:09

Vivienne Fosh


Two step solution:

1) Select the video file from the gallery.

Create a global int private static final int SELECT_VIDEO = 3; -- it doesn't matter what number you use, so long as that's to one you check for later on. Then, use an intent to select a video.

Intent intent = new Intent();
intent.setType("video/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent,"Select a Video "), SELECT_VIDEO);

Use onActivityResult() to start the uploadVideo() method.

public void onActivityResult(int requestCode, int resultCode, Intent data) {

    if (resultCode == RESULT_OK) {

        if (requestCode == SELECT_VIDEO)
        {
            System.out.println("SELECT_VIDEO");
            Uri selectedImageUri = data.getData();
            selectedPath = getPath(selectedImageUri);
            System.out.println("SELECT_VIDEO Path : " + selectedPath);

            uploadVideo(selectedPath);        
    }

2) Go to http://hc.apache.org/downloads.cgi, download the latest HttpClient jar, add it to your project, and upload the video using the following method:

private void uploadVideo(String videoPath) throws ParseException, IOException {

    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost(YOUR_URL);

    FileBody filebodyVideo = new FileBody(new File(videoPath));
    StringBody title = new StringBody("Filename: " + videoPath);
    StringBody description = new StringBody("This is a video of the agent");
    StringBody code = new StringBody(realtorCodeStr);

    MultipartEntity reqEntity = new MultipartEntity();
    reqEntity.addPart("videoFile", filebodyVideo);
    reqEntity.addPart("title", title);
    reqEntity.addPart("description", description);
    reqEntity.addPart("code", code);
    httppost.setEntity(reqEntity);

    // DEBUG
    System.out.println( "executing request " + httppost.getRequestLine( ) );
    HttpResponse response = httpclient.execute( httppost );
    HttpEntity resEntity = response.getEntity( );

    // DEBUG
    System.out.println( response.getStatusLine( ) );
    if (resEntity != null) {
      System.out.println( EntityUtils.toString( resEntity ) );
    } // end if

    if (resEntity != null) {
      resEntity.consumeContent( );
    } // end if

    httpclient.getConnectionManager( ).shutdown( );
} // end of uploadVideo( )

Once you have it working you'll probably want to put it in a thread and add an uploading dialog, but this will get you started. Working for me after I unsuccessfully tried the upload2Server() method. This will also work for images and audio with some minor tweaking.

like image 40
Kyle Clegg Avatar answered Sep 20 '22 14:09

Kyle Clegg