I tried the following but on response i am getting 500 error (Internal Server Error) -- help me design the interface for the request in the above screenshot...thanks
@Multipart
@POST("myrecord")
Call<ResponseBody> addRecord(@Query("token") String token,@Query("userid") int userId,
@Query("name") String name, @Part("file") RequestBody file);
File file = new File(getRealPathFromURI(data.getData()));
RequestBody requestFile = RequestBody.create(MediaType.parse("image/*"), getRealPathFromURI(data.getData()));`
Call<ResponseBody> responseBodyCall = service.addRecord(token, userId,
"newFileName", requestFile);
responseBodyCall.enqueue(new Callback<ResponseBody>() {
@Override
public void onResponse(Call<ResponseBody> call, Response<ResponseBody> response) {
Log.d("Response", "="+response.code());
Log.d("Response", "= "+response.message());
}
@Override
public void onFailure(Call<ResponseBody> call, Throwable t) {
Log.d("failure", "message = " + t.getMessage());
Log.d("failure", "cause = " + t.getCause());
}
});`
The following code worked :)
@Multipart
@POST("myrecord")
Call<ResponseBody> addRecord(@Query("token") String token, @Query("userid") int userId,
@Query("name") String name, @Part MultipartBody.Part file);
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if ((requestCode == FILE_SELECT_CODE) && (resultCode == -1)) {
File file = new File(getRealPathFromURI(data.getData()));
RequestBody requestFile = RequestBody.create(MediaType.parse("multipart/form-data"), getRealPathFromURI(data.getData()));
MultipartBody.Part multipartBody =MultipartBody.Part.createFormData("file",file.getName(),requestFile);
Call<ResponseBody> responseBodyCall = service.addRecord(token, userId, "fileName", multipartBody);
responseBodyCall.enqueue(new Callback<ResponseBody>() {
@Override
public void onResponse(Call<ResponseBody> call, Response<ResponseBody> response) {
Log.d("Success", "success "+response.code());
Log.d("Success", "success "+response.message());
}
@Override
public void onFailure(Call<ResponseBody> call, Throwable t) {
Log.d("failure", "message = " + t.getMessage());
Log.d("failure", "cause = " + t.getCause());
}
});
}
}
@Multipart
@POST("myrecord")
Call<ResponseBody> addRecord(@Part("file") RequestBody file,@Part MultipartBody.Part file,
@Query("token") String token,@Query("userid") int userId,@Query("name") String name);
RequestBody requestFile =
RequestBody.create(MediaType.parse("multipart/form-data"), file);
MultipartBody.Part body =
MultipartBody.Part.createFormData("picture", file.getName(), requestFile);
String descriptionString = "your description";
RequestBody description =
RequestBody.create(
MediaType.parse("multipart/form-data"), descriptionString);
for more information look into this link: https://futurestud.io/blog/retrofit-2-how-to-upload-files-to-server
If you would like to send file as binary in a body without using multipart you can remove @Multipart
annotation from your code and use @Body
annotation. It looks like
@POST("myrecord")
Call<ResponseBody> addRecord(@Query("token") String token,@Query("userid") int userId,
@Query("name") String name, @Body RequestBody file);
File file = new File(getRealPathFromURI(data.getData()));
RequestBody requestFile = RequestBody.create(MediaType.parse("image/*"), getRealPathFromURI(data.getData()));
Call<ResponseBody> responseBodyCall = service.addRecord(token, userId,
"newFileName", requestFile);
responseBodyCall.enqueue(new Callback<ResponseBody>() {
@Override
public void onResponse(Call<ResponseBody> call, Response<ResponseBody> response) {
Log.d("Response", "="+response.code());
Log.d("Response", "= "+response.message());
}
@Override
public void onFailure(Call<ResponseBody> call, Throwable t) {
Log.d("failure", "message = " + t.getMessage());
Log.d("failure", "cause = " + t.getCause());
}
});`
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