UPDATE AND INSERT multiple rows into MySQL database

Question

I wrote this code to insert multiple rows into database, and I need to update duplicates .

    INSERT INTO `me_cities`( `from`, `destination`, `price`, `updated`)
 VALUES 
('ERR','MRHD','91,000',now()),
('ERR','KIH','106,800',now()),
('ERR','SYZ','86,000',now()),
('ERR','AWZ','121,000',now()),
('ERR','IFN','116,741',now()),
('ERR','GSM','111,000',now()),
('ERR','NJF','141,000',now()),
('ERR','IST','351,000',now()),
('ERR','BND','116,000',now()),
('ERR','DEF','120,200',now()),
('ERR','','151,000',now()),
('ERR','BUZ','161,000',now()) 
    ON DUPLICATE KEY UPDATE `price`=VALUES(price),`updated`=VALUES(now());

But I have error on this query. I need to update the row if only from and destination field are as same as next row.

Answer 1

If I got your topic , I think you should do something like this :

 INSERT INTO `me_cities`( `from`, `destination`, `price`, `updated`)
 VALUES 
('ERR','MRHD','91,000',now()),
('ERR','KIH','106,800',now()),
('ERR','SYZ','86,000',now()),
('ERR','AWZ','121,000',now()),
('ERR','IFN','116,741',now()),
('ERR','GSM','111,000',now()),
('ERR','NJF','141,000',now()),
('ERR','IST','351,000',now()),
('ERR','BND','116,000',now()),
('ERR','DEF','120,200',now()),
('ERR','','151,000',now()),
('ERR','BUZ','161,000',now())
    ON DUPLICATE KEY UPDATE `price`=VALUES(`price`),`updated`=VALUES(`updated`);

UPDATE , if you want to update every each of them, first make the from and destination columns unique and relevant unique keys , something like this query

  INSERT INTO `me_cities`( `from`, `destination`, `price`, `updated`)
     VALUES 
    ('ERR','MRHD','91,000',now()) ON DUPLICATE KEY UPDATE `price`=''  ,`updated`=now() ;
INSERT INTO `me_cities`( `from`, `destination`, `price`, `updated`)
     VALUES 
    ('ERR','MRHD','91,000',now())ON DUPLICATE KEY UPDATE `price`=''  ,`updated`=now() ;