unusual function pointer parameter syntax

Question

is there any difference between this two syntaxes?

void fun( void (*funptr)() )
{
    funptr(); // calls the function
}

void fun( void funptr() )
{
    funptr(); // calls the function
}

i'd always been using the first form, but i've just seen the second one and it seems it behaves exactly the same, while the syntax is clearer.

Answer 1

There is no difference. In both cases, funptr has type void (*)(), a function pointer type.

C99 standard, section 6.7.5.3, paragraph 8:

A declaration of a parameter as ‘‘function returning type’’ shall be adjusted to ‘‘pointer to function returning type’’, as in 6.3.2.1.