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unix timestamp to boost::posix_time::ptime

I need to convert double with number of seconds since the epoch to ptime. I'm prety sure there must be an easy way to do this, but I couldn't find anything. Thanks.

Edit: The original timestamp is floating point. I can't change it and i don't want to lose the sub-second precision.

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cube Avatar asked Jul 22 '09 19:07

cube


3 Answers

Use the from_time_t() conversion function. A time_t is a UNIX timestamp, i.e. the number of seconds since the epoch.

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John Kugelman Avatar answered Nov 07 '22 06:11

John Kugelman


For a machine that has boost date/time compiled to the default level of microsecond resolution, try this:

double ts = 1250524800.5;
// Use floor() here if seconds are always positive.
time_t secondsSinceEpoch = floor(ts);
long microsecondsSinceSecond =
    floor((ts - static_cast<double>(secondsSinceEpoch)) * 1000000);
boost::posix_time::ptime result =
    boost::posix_time::from_time_t(secondsSinceEpoch);
boost::posix_time::time_duration fractionalSeconds(0, 0, 0,
                                                   microsecondsSinceSecond);
result += fractionalSeconds;
cout << "Time stamp is " << result << endl;

The output for this is "Time stamp is 2009-Aug-17 16:00:00.500000" on my linux box.

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BD at Rivenhill Avatar answered Nov 07 '22 05:11

BD at Rivenhill


after some fiddling around i came up with this:

ptime(date(1970, 1, 1), time_duration(0, 0, 0, time_duration::ticks_per_second() * 1234567890.0987654321))

I'm not sure this is the best solution, but it seems to do what i need.

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cube Avatar answered Nov 07 '22 05:11

cube