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Unit testing for object immutability

I want to make sure that a given group of objects is immutable.

I was thinking about something along the lines of:

  1. check if every field is private final
  2. check if class is final
  3. check for mutable members

So I guess my question is: is 3. possible ?

I can check recursively whether every member of a class has its fields private final, but this is not enough since a class can have e method named getHaha(param) which adds the given param to an array for instance.

So is there a good way to check if an object is immutable or is it even possible ?

Thanks,

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Simeon Avatar asked Jul 19 '11 07:07

Simeon


1 Answers

Yes, you can write an immutability detector.

First of all, you are not going to be just writing a method which determines whether a class is immutable; instead, you will need to write an immutability detector class, because it is going to have to maintain some state. The state of the detector will be the detected immutability of all classes which it has examined so far. This is not only useful for performance, but it is actually necessary because a class may contain a circular reference, which would cause a simplistic immutability detector to fall into infinite recursion.

The immutability of a class has four possible values: Unknown, Mutable, Immutable, and Calculating. You will probably want to have a map which associates each class that you have encountered so far to an immutability value. Of course, Unknown does not actually need to be implemented, since it will be the implied state of any class which is not yet in the map.

So, when you begin examining a class, you associate it with a Calculating value in the map, and when you are done, you replace Calculating with either Immutable or Mutable.

For each class, you only need to check the field members, not the code. The idea of checking bytecode is rather misguided.

First of all, you should not check whether a class is final; The finality of a class does not affect its immutability. Instead, a method which expects an immutable parameter should first of all invoke the immutability detector to assert the immutability of the class of the actual object that was passed. This test can be omitted if the type of the parameter is a final class, so finality is good for performance, but strictly speaking not necessary. Also, as you will see further down, a field whose type is of a non-final class will cause the declaring class to be considered as mutable, but still, that's a problem of the declaring class, not the problem of the non-final immutable member class. It is perfectly fine to have a tall hierarchy of immutable classes, in which all the non-leaf nodes must of course be non-final.

You should not check whether a field is private; it is perfectly fine for a class to have a public field, and the visibility of the field does not affect the immutability of the declaring class in any way, shape, or form. You only need to check whether the field is final and its type is immutable.

When examining a class, what you want to do first of all is to recurse to determine the immutability of its super class. If the super is mutable, then the descendant is by definition mutable too.

Then, you only need to check the declared fields of the class, not all fields.

If a field is non-final, then your class is mutable.

If a field is final, but the type of the field is mutable, then your class is mutable. (Arrays are by definition mutable.)

If a field is final, and the type of the field is Calculating, then ignore it and proceed to the next field. If all fields are either immutable or Calculating, then your class is immutable.

If the type of the field is an interface, or an abstract class, or a non-final class, then it is to be considered as mutable, since you have absolutely no control over what the actual implementation may do. This might seem like an insurmountable problem, because it means that wrapping a modifiable collection inside an UnmodifiableCollection will still fail the immutability test, but it is actually fine, and it can be handled with the following workaround.

Some classes may contain non-final fields and still be effectively immutable. An example of this is the String class. Other classes which fall into this category are classes which contain non-final members purely for performance monitoring purposes (invocation counters, etc.), classes which implement popsicle immutability (look it up), and classes which contain members that are interfaces which are known to not cause any side effects. Also, if a class contains bona fide mutable fields but promises not to take them into account when computing hashCode() and equals(), then the class is of course unsafe when it comes to multi-threading, but it can still be considered as immutable for the purpose of using it as a key in a map. So, all these cases can be handled in one of two ways:

  1. Manually adding classes (and interfaces) to your immutability detector. If you know that a certain class is effectively immutable despite the fact that the immutability test for it fails, you can manually add an entry to your detector which associates it with Immutable. This way, the detector will never attempt to check whether it is immutable, it will always just say 'yes, it is.'

  2. Introducing an @ImmutabilityOverride annotation. Your immutability detector can check for the presence of this annotation on a field, and if present, it may treat the field as immutable despite the fact that the field may be non-final or its type may be mutable. The detector may also check for the presence of this annotation on the class, thus treating the class as immutable without even bothering to check its fields.

I hope this helps future generations.

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Mike Nakis Avatar answered Oct 15 '22 21:10

Mike Nakis