I m trying to extract lines from a log file , using that code :
with open('fichier.01') as f:
content = f.readlines()
print (content)
but its always makes the error statement
Traceback (most recent call last):
File "./parsepy", line 4, in <module>
content = f.readlines()
File "/usr/lib/python3.5/codecs.py", line 321, in decode
(result, consumed) = self._buffer_decode(data, self.errors, final)
UnicodeDecodeError: 'utf-8' codec can't decode byte 0xe9 in position 2213: invalid continuation byte
how can i fix it ??
The Python "UnicodeDecodeError: 'utf-8' codec can't decode byte in position: invalid continuation byte" occurs when we specify an incorrect encoding when decoding a bytes object. To solve the error, specify the correct encoding, e.g. latin-1 .
The Python "UnicodeDecodeError: 'ascii' codec can't decode byte in position" occurs when we use the ascii codec to decode bytes that were encoded using a different codec. To solve the error, specify the correct encoding, e.g. utf-8 . Here is an example of how the error occurs. I have a file called example.
try one of the following
open('fichier.01', 'rb')
open('fichier.01', encoding ='utf-8')
open('fichier.01', encoding ='ISO-8859-1')
or also you can use io Module:
import io
io.open('fichier.01')
This is a common error when opening files when using Python (or any language really). This is an error you will soon learn to catch.
If it's not encoded as text then you will have to open it in binary mode e.g.:
with open('fichier.01', 'rb') as f:
content = f.readlines()
If it's encoded as something other than UTF-8 and it can be opened in text mode then open
takes an encoding
argument: https://docs.python.org/3.5/library/functions.html#open
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With