unicode string equivalent of contain

Question

I have an error when trying to use contain in python.

s = u"some utf8 words" k = u"one utf8 word"  if s.contains(k):     print "contains"  

How do i achieve the same result?

Example with normal ASCII string

s = "haha i am going home" k = "haha"  if s.contains(k):     print "contains" 

I am using python 2.7.x

Answer 1

The same for ascii and utf8 strings:

if k in s:     print "contains"  

There is no contains() on either ascii or uft8 strings:

>>> "strrtinggg".contains AttributeError: 'str' object has no attribute 'contains' 

---

What you can use instead of contains is find or index:

if k.find(s) > -1:     print "contains" 

or

try:     k.index(s) except ValueError:     pass  # ValueError: substring not found else:     print "contains" 

But of course, the in operator is the way to go, it's much more elegant.