I'm getting into promises pattern with Q and I keep getting warning "[Q] Unhandled rejection reasons (should be empty)" in console. What em I doing wrong?
http://jsfiddle.net/FpyDr/1/
function load(url) {
var deferred = Q.defer();
$.ajax({
type: "GET",
processData: false,
dataType: "html",
url: url,
cache: false
}).done(function (response, status, xhr) {
deferred.reject(new Error("test error"));
return;
}).fail(function (xhr, status, error) {
deferred.reject(new Error("ajax failed"));
return;
});
return deferred.promise;
}
load("http://fiddle.jshell.net")
.then(function (result) {
console.log("got result", typeof(result));
})
.catch(function (error) {
console.log("got error", error);
return true;
})
.done();
If an error condition arises inside a promise, you “reject” the promise by calling the reject() function with an error. To handle a promise rejection, you pass a callback to the catch() function. This is a simple example, so catching the rejection is trivial.
The Promise. reject() method returns a Promise object that is rejected with a given reason. The unhandledrejection event is sent to the global scope of a script when a JavaScript Promise that has no rejection handler is rejected; typically, this is the window, but may also be a Worker.
Based on this confusing discussion it's a false positive.
To silence the logging you can do this:
Q.stopUnhandledRejectionTracking();
If you didn't capture the rejection it would throw the error, so you'll still see it in the console after adding the code above. JSFiddle: http://jsfiddle.net/homeyer/FpyDr/22/
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