Good day,
When trying to understand the Mathematica's evaluation sequence by using standard Trace
and TraceScan
commands and their nice visual representations developed in the recent thread, I faced some ambiguities in their behavior.
First of all, when I evaluate
In[1]:= Trace[a+1,TraceOriginal->True]
I get
Out[1]= {a+1,{Plus},{a},{1},a+1,1+a,{Plus},{1},{a},1+a}
All sublists correspond to sub-evaluations (as it is stated in the Documentation). The last expression 1+a
probably corresponds to the result of the evaluation although it is not clearly stated in the Documentation. But what exactly mean expressions a+1
and 1+a
in the middle of the list? To which evaluation steps of the standard evaluation sequence they correspond?
The second oddity is with TraceScan
. Consider the following:
In[1]:= list={}; TraceScan[AppendTo[list,StyleForm[#,"Input"]]&,(a+1),_,AppendTo[list,#]&]; list
Out[1]= {a+1, Plus, Plus, a, a, 1, 1, 1+a, Plus, Plus, 1, 1, a, a, 1+a, a+1}
You can see that the last two expressions in the list are 1+a
and a+1
. Both are results of (sub)evaluations. But the real output is 1+a
and so I do not understand why a+1
is at the end of the evaluation chain? And why is no there a+1
in the middle of the evaluation chain as it was in the case of Trace
? Is it a bug?
P.S. These results are reproduced with Mathematica 7.0.1 and 5.2.
The fp
argument to TraceScan
is called with two arguments. The first is the original unevaluated expression. The second is the result of the evaluation. In your example, the second AppendTo
is using the first argument so you are seeing the unevaluated expression. Change #
to #2
and then you will see the results you expect.
Also note that the second argument is not wrapped in HoldForm
(documentation notwithstanding), so in general one must take care to use a function that holds its arguments for the fp
argument to avoid generating spurious evaluations.
Comparing Trace and TraceScan
The behaviour of Trace
is described in considerable detail in the Mathematica 8 documentation. It states that, by default, Trace
only shows expressions after the head and arguments have been evaluated. Thus, we see a sequence like this:
In[28]:= SetAttributes[f, Orderless]
Trace[f[a, 1]]
Out[29]= {f[a,1],f[1,a]}
Only the input expression and its result is shown. The TraceOriginal
options controls (quote) "whether to look at expressions before their heads and arguments are evaluated". When this option is True
then the output is supplemented with the head and argument expressions:
In[30]:= Trace[f[a,1], TraceOriginal->True]
Out[30]= {f[a,1],{f},{a},{1},f[a,1],f[1,a]}
The first element of the new list is the original expression before the head and arguments are evaluated. Then we see the head and arguments being evaluated. Finally, we see the top-level expressions again, after the head and arguments have been evaluated. The last two elements of the list match the two elements of the original trace output.
As the linked documentation states, Trace
is very selective about what expressions it returns. For example, it omits trivial evaluation chains completely. TraceScan
is comprehensive and calls the supplied functions for every evaluation, trivial or not. You can see the comprehensive set of evaluations using the following TraceScan
expression:
TraceScan[Print, f[a,1], _, Print[{##}]&]
The following table matches the output produced by Trace
with and without TraceOriginal
, along with the output of the TraceScan
expression:
Trace Trace TraceScan
Original
f[a,1] f[a,1]
f
{f} {f
,f}
a
{a} {a
,a}
1
{1} {1
,1}
f[1,a]
{f[1,a]
,f[1,a]}
f[a,1] f[a,1] {f[a,1]
f[1,a] f[1,a] ,f[1,a]}
There is certain amount of speculation in this table about which entry matches against which, given that the internals of Trace
are inaccessible. Further experiments might give information that adjusts the alignment. However, the key point is that all of the information generated by Trace
is available using TraceScan
-- and TraceScan
provides more.
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