I am using the Python API for Tensorflow. I am trying to implement the Rosenbrock function given below without the use of a Python loop:
My current implementation is as follows:
def rosenbrock(data_tensor):
columns = tf.unstack(data_tensor)
summation = 0
for i in range(1, len(columns) - 1):
first_term = tf.square(tf.subtract(columns[i + 1], tf.square(columns[i])))
second_term = tf.square(tf.subtract(columns[i], 1.0))
summation += tf.add(tf.multiply(100.0, first_term), second_term)
return summation
I have tried implementing the summation in a tf.while_loop()
; however, I found the API somewhat unintuitive when it comes to using an index integer that is meant to remain separate from the data. The example given in the documentation uses the data as the index (or vice-versa):
i = tf.constant(0)
c = lambda i: tf.less(i, 10)
b = lambda i: tf.add(i, 1)
r = tf.while_loop(c, b, [i])
To iterate through a tensor in Python, we can easily use the for loop method and it will iterate through the tensor directly. To iterate over tensor defines that we have to print a new line tensor and also it will return the number of elements in the tensor.
In the TensorFlow. js library, the tf. tile() function is used to create a new tensor by duplicating the elements in the existing tensor. It takes two parameters.
tf. constant is useful for asserting that the value can be embedded that way. If the argument dtype is not specified, then the type is inferred from the type of value . # Constant 1-D Tensor from a python list. tf.
For example, suppose you have a tensor filled with integer numbers and you want to check the shape of the given input tensor. To do this task we can easily use the tf. shape() function and it returns the shape property as a scaler input value.
This can be achieved using the tf.while_loop()
and standard tuples as per the second example in the documentation.
def rosenbrock(data_tensor):
columns = tf.unstack(data_tensor)
# Track both the loop index and summation in a tuple in the form (index, summation)
index_summation = (tf.constant(1), tf.constant(0.0))
# The loop condition, note the loop condition is 'i < n-1'
def condition(index, summation):
return tf.less(index, tf.subtract(tf.shape(columns)[0], 1))
# The loop body, this will return a result tuple in the same form (index, summation)
def body(index, summation):
x_i = tf.gather(columns, index)
x_ip1 = tf.gather(columns, tf.add(index, 1))
first_term = tf.square(tf.subtract(x_ip1, tf.square(x_i)))
second_term = tf.square(tf.subtract(x_i, 1.0))
summand = tf.add(tf.multiply(100.0, first_term), second_term)
return tf.add(index, 1), tf.add(summation, summand)
# We do not care about the index value here, return only the summation
return tf.while_loop(condition, body, index_summation)[1]
It is important to note that the index increment should occur in the body of the loop similar to a standard while loop. In the solution given, it is the first item in the tuple returned by the body()
function.
Additionally, the loop condition function must allot a parameter for the summation although it is not used in this particular example.
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