Underscore: remove all key/value pairs from an array of object

Question

Is there a "smart" underscore way of removing all key/value pairs from an array of object?

e.g. I have following array:

var arr = [         { q: "Lorem ipsum dolor sit.", c: false },         { q: "Provident perferendis veniam similique!", c: false },         { q: "Assumenda, commodi blanditiis deserunt?", c: true },         { q: "Iusto, dolores ea iste.", c: false },     ]; 

and I want to get the following:

var newArr = [         { q: "Lorem ipsum dolor sit." },         { q: "Provident perferendis veniam similique!" },         { q: "Assumenda, commodi blanditiis deserunt?" },         { q: "Iusto, dolores ea iste." },     ]; 

I can get this working with the JS below, but not really happy with my solutions:

for (var i = 0; i < arr.length; i++) {     delete arr[i].c; }; 

Any suggestions much appreciated.

Answer 1

You can use map and omit in conjunction to exclude specific properties, like this:

var newArr = _.map(arr, function(o) { return _.omit(o, 'c'); }); 

Or map and pick to only include specific properties, like this:

var newArr = _.map(arr, function(o) { return _.pick(o, 'q'); });