Underscore is not working in oracle like clause

Question

When development, I used 'test_1%' to find 'test_123' in like. But in production environment its not working. Using 'escape '\'' is working. is there any setting needs to set in oracle? I want to use without escape '\''.

Answer 1

try this in SQL Developer:

SELECT * FROM TABLE1 WHERE NAME LIKE 'test\_1%' escape '\' 

in sql plus:

set escape '\' SELECT * FROM TABLE1 WHERE NAME LIKE 'test\_1%'; 

Answer 2

The other answers using the ESCAPE '\' didn't work for me, but I was able to overcome this issue by using a REPLACE function:

SELECT * FROM name_of_table WHERE REPLACE(description, '_', '~') LIKE 'testing~%';

Answer 3

In Oracle, you can also use ESCAPE like this:

SELECT * FROM name_of_table WHERE description LIKE 'testing\_%' ESCAPE '\';