Can someone explain me what exactly is going on here? I am not fully getting into it right now:
val s = Seq(1D,2D,3D,4D)
case class WithUnit(value: Double, unit: String)
s map { WithUnit(_,"cm") } // works
s map { WithUnit(value = _ , unit = "cm") } // error: missing parameter type for expanded function ((x$2) => value = x$2)
I guess the compiler can´t infer the parameter type because I wrote the name of the argument. But why not? It shouldn´t be more difficult only because of stating the name of the argument?!
Thanks!
When you wrote:
WithUnit(value = _, unit = "cm")
You wanted it to mean:
x => WithUnit(value = x, unit = "cm")
But if you take a close look at the error message, you'll see that the compiler didn't see it that way, it parsed it as:
WithUnit(x => value = x, unit = "cm"})
As you can see, the _ is scoped more tightly than you wanted.
_ always picks the tightest non-degenerate scope it can. The scope is determined purely syntactically, during parsing, without regard to types.
By non-degenerate, I mean that the compiler didn't think you meant:
WithUnit(value = x => x, unit = "cm")
Tightest non-degenerate scope means the scope defined by the innermost function parenthesis relative to the underscore. Without such a rule the compiler wouldn't be able to know which _ corresponds to which function when function calls are nested.
Try this:
scala> val withUnits = s map { x => WithUnit(value = x, unit = "cm") }
withUnits: Seq[WithUnit] = List(WithUnit(1.0,cm), WithUnit(2.0,cm), WithUnit(3.0,cm), WithUnit(4.0,cm))
The problem is the usage of the underscore to directly define an anynymous function.
A detailed description is in chapter 8.5. Placeholder syntax in the "Programming in Scala" book.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With