Undefined variable error in PHP include file [duplicate]

Question

Possible Duplicate:
Undefined variable problem with PHP function

Can someone tell me why I keep getting undefined variable error messages in my PHP include files?

<?php

$page = 1;

if (isset($_REQUEST['page'])) {
  $page = $_REQUEST['page'];
}

function phpRocks() {
  require("includes/dostuff.php");
}

if ($search) {
  phpRocks();
}

?>

Then in dostuff.php:

<?php echo $page; ?>

This is the error I'm getting:

Notice: Undefined variable: page in /dostuff.php on line 61

Attn down voters/close requesters: Doesn't show any research effort? How so? What else should I have added? I have been stumped over this for a half hour and cannot find any other posts that answer this question. Do I need to be a PHP expert in order to post questions (therefore I wouldn't be posting any questions!)??

Answer 1

mario's got it. Do this:

function phpRocks() {
    global $page;

    require("includes/dostuff.php");
}

Answer 2

You are including the file inside a function. Therefore the scope of all the included code is the scope of the function. The variable $page does not exist inside the function. Pass it in:

function phpRocks($page) {
    require "includes/dostuff.php";
}

phpRocks($page);