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If I have an array in PHP that is currently null, shouldn't accessing an undefined index present an E_NOTICE level error?
If I have the following snippet of code:
$myArray = null;
echo $myArray['foo']['bar'];
I would expect an error but it runs without issue. I've verified my log level to be set to E_ALL. Is there something I'm missing or is PHP happy returning null for undefined indexes as long as you aren't trying to modify the data?
220
When using them, you might encounter an error called “Notice: Undefined Index”. This error means that within your code, there is a variable or constant that has no value assigned to it. But you may be trying to use the values obtained through the user form in your PHP code.
To resolve undefined index error, we make use of a function called isset() function in PHP. To ignore the undefined index error, we update the option error_reporting to ~E_NOTICE to disable the notice reporting.
Undefined Index in PHP is a Notice generated by the language. The simplest way to ignore such a notice is to ask PHP to stop generating such notices. You can either add a small line of code at the top of the PHP page or edit the field error_reporting in the php. ini file.
You can use the PHP isset() function to test whether a variable is set or not. The isset() will return FALSE if testing a variable that has been set to NULL.
Yes, the undefined index only triggers for not null variables (don't ask me why). This will trigger a notice though:
<?php
error_reporting(E_ALL);
$myArray = array();
echo $myArray['foo']['bar'];
?>
no, it doesn't show any error when $myArray is set to null. if it is an empty array or any other value except for null then it returns a E_NOTICE level error. i actualy don't know why but it is as it is.
39
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