When I do this
String datum = "20130419233512"; DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMddHHmmss").withZone(ZoneId.of("Europe/Berlin")); OffsetDateTime datetime = OffsetDateTime.parse(datum, formatter);
I get the following exception:
java.time.format.DateTimeParseException: Text '20130419233512' could not be parsed: Unable to obtain OffsetDateTime from TemporalAccessor: {InstantSeconds=1366407312},ISO,Europe/Berlin resolved to 2013-04-19T23:35:12 of type java.time.format.Parsed
How can I parse my datetime string so that it is interpreted as always being from the timezone "Europe/Berlin" ?
The problem is that there is a difference between what a ZoneId
is and a ZoneOffset
is. To create a OffsetDateTime
, you need an zone offset. But there is no one-to-one mapping between a ZoneId
and a ZoneOffset
because it actually depends on the current daylight saving time. For the same ZoneId
like "Europe/Berlin", there is one offset for summer and a different offset for winter.
For this case, it would be easier to use a ZonedDateTime
instead of an OffsetDateTime
. During parsing, the ZonedDateTime
will correctly be set to the "Europe/Berlin"
zone id and the offset will also be set according to the daylight saving time in effect for the date to parse:
public static void main(String[] args) { String datum = "20130419233512"; DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMddHHmmss").withZone(ZoneId.of("Europe/Berlin")); ZonedDateTime datetime = ZonedDateTime.parse(datum, formatter); System.out.println(datetime.getZone()); // prints "Europe/Berlin" System.out.println(datetime.getOffset()); // prints "+02:00" (for this time of year) }
Note that if you really want an OffsetDateTime
, you can use ZonedDateTime.toOffsetDateTime()
to convert a ZonedDateTime
into an OffsetDateTime
.
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