I have the next value
value = bytearray(b'\x85\x13\xbd|\xfb\xbc\xc3\x95\xbeL6L\xfa\xbf0U_`$]\xca\xee]z\xef\xa0\xd6(\x15\x8b\xca\x0e\x1f7\xa9\xf0\xa4\x98\xc5\xdf\xcdM5\xef\xc2\x052`\xeb\x13\xd9\x99B.\x95\xb2\xbd\x96\xd9\x14\xe6F\x9e\xfd\xd8\x00')
when I try to convert in python3.x it works well.
>>> int.from_bytes(value, byteorder='little')
2909369579440607969688280064437289348250138784421305732473112318543540722321676649649580720015118044118243611774710427666475769804427735898727217762490192773
How to convert it in python2.7? I already read the convert a string of bytes into an int (python)
struct.unpack(fmt, value)[0]
But don't know what to do with fmt.
You can just write your own from_bytes function in Python 2:
def from_bytes (data, big_endian = False):
if isinstance(data, str):
data = bytearray(data)
if big_endian:
data = reversed(data)
num = 0
for offset, byte in enumerate(data):
num += byte << (offset * 8)
return num
Used like this:
>>> data = b'\x85\x13\xbd|\xfb\xbc\xc3\x95\xbeL6L\xfa\xbf0U_`$]\xca\xee]z\xef\xa0\xd6(\x15\x8b\xca\x0e\x1f7\xa9\xf0\xa4\x98\xc5\xdf\xcdM5\xef\xc2\x052`\xeb\x13\xd9\x99B.\x95\xb2\xbd\x96\xd9\x14\xe6F\x9e\xfd\xd8\x00'
>>> from_bytes(data)
2909369579440607969688280064437289348250138784421305732473112318543540722321676649649580720015118044118243611774710427666475769804427735898727217762490192773L
As for struct, you cannot really use this, as it only supports unpacking elements of a certain kind, up to 8 byte integers. But since you want to handle arbitrary byte strings, you will have to use something else.
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