Assume that I have the following mutable class:
class Foo {
constructor(public bar: any) { }
}
I can define readonly instances of this class like so:
const foo: Readonly<Foo> = new Foo(123);
foo.bar = 456; // error, can't reassign to bar because it's readonly.
What I'd like to be able to do is the inverse of this, where the class is immutable:
class Foo {
constructor(public readonly bar: any) { }
}
And then be able to make mutable versions like so:
const foo: Mutable<Foo> = new Foo(123);
foo.bar = 456;
Is this possible?
Yes, you can use -readonly in type definition.
type Mutable<T> = {
-readonly [P in keyof T]: T[P];
};
const foo: Mutable<Foo> = new Foo(123);
foo.bar = 456;
Playground
But remember it's only type definition, it doesn't change original logic.
type Mutable<T> = {
-readonly [P in keyof T]: T[P];
};
class Foo {
get test(): boolean {
return true;
}
constructor(public readonly bar: any) { }
}
const foo: Mutable<Foo> = new Foo(123);
foo.bar = 456;
foo.test = false; // oops, it will cause an error.
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