Say I have a type like so:
interface IAll {
foo: boolean,
bar: Function,
baz: number
}
instead of manually defining all the possible subtypes of IAll
, like so:
interface IAll1 {
foo: boolean,
bar: Function,
}
interface IAll2 {
bar: Function,
baz: number
}
interface IAll3 {
foo: boolean,
}
interface IAll4 {
foo: boolean,
}
...etc
and then doing
type IAll = IAll1 | IAll2 | IAll3 ... etc.
Is there a way for TypeScript to statically check whether an object is a subtype or subset of another?
This is useful for some cases where we combine several subtypes or subsets to form a full type.
Custom Type Syntax In TypeScript, the syntax for creating custom types is to use the type keyword followed by the type name and then an assignment to a {} block with the type properties.
In TypeScript, object is the type of all non-primitive values (primitive values are undefined , null , booleans, numbers, bigints, strings). With this type, we can't access any properties of a value.
TypeScript allows us to not only create individual types, but combine them to create more powerful use cases and completeness. There's a concept called “Intersection Types” in TypeScript that essentially allows us to combine multiple types.
You can use Partial<T>
. This will make all the properties in IAll
optional:
type SubsetOfIAll = Partial<IAll>;
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