TypeError: Missing 1 required positional argument: 'self'

Question

I can't get past the error:

Traceback (most recent call last):   File "C:\Users\Dom\Desktop\test\test.py", line 7, in <module>     p = Pump.getPumps() TypeError: getPumps() missing 1 required positional argument: 'self' 

I examined several tutorials but there doesn't seem to be anything different from my code. The only thing I can think of is that Python 3.3 requires different syntax.

class Pump:      def __init__(self):         print("init") # never prints      def getPumps(self):         # Open database connection         # some stuff here that never gets executed because of error         pass  # dummy code  p = Pump.getPumps()  print(p) 

If I understand correctly, self is passed to the constructor and methods automatically. What am I doing wrong here?

Answer 1

You need to instantiate a class instance here.

Use

p = Pump() p.getPumps() 

Small example -

>>> class TestClass:         def __init__(self):             print("in init")         def testFunc(self):             print("in Test Func")   >>> testInstance = TestClass() in init >>> testInstance.testFunc() in Test Func