TypeError: execv() arg 2 must contain only strings

Question

I am getting the following error when running the script below,can anyhelp to identify what the problem is and how to overcome it

import subprocess
import sys
import os

def main ():
    to = ''
    ssh_command = ["ssh", "-p", "29418", "review-android.quicinc.com", "gerrit",
                   "query", "--format=JSON", "--current-patch-set",
                   "--commit-message", "--files", ]

    with open('gerrit_output.txt', 'a') as fp:
        with open('caf_gerrits.txt','r') as f :
            for gerrit in f :
                print gerrit
                result = subprocess.check_output(ssh_command + [gerrit, ])
                print result
                fp.write(result)

if __name__ == '__main__':
main()

ERROR:-

545804

Traceback (most recent call last):
  File "test.py", line 20, in <module>

  File "test.py", line 15, in main

  File "/usr/lib/python2.7/subprocess.py", line 537, in check_output
    process = Popen(stdout=PIPE, *popenargs, **kwargs)
  File "/usr/lib/python2.7/subprocess.py", line 679, in __init__
    errread, errwrite)
  File "/usr/lib/python2.7/subprocess.py", line 1249, in _execute_child
    raise child_exception
TypeError: execv() arg 2 must contain only strings

Answer 1

The third element in ssh_command is an integer. It needs to be a string.

e.g:

ssh_command = ["ssh", "-p", 29418, ...
#                            ^ problem

And the solution is simple, just add some quotes:

ssh_command = ["ssh", "-p", "29418", ...
#                           ^Now it's a string.