TypeError: count() takes exactly one argument

Question

I'm new to Python and Django, and I modified this code from a tutorial. I'm getting TypeError: count() takes exactly one argument (0 given) when I load the page. I've been troubleshooting and googling and can't seem to figure it out. What am I doing wrong?

def report(request):
    flashcard_list = []
    for flashcard in Flashcard.objects.all():
        flashcard_dict = {}
        flashcard_dict['list_object'] = flashcard_list
        flashcard_dict['words_count'] = flashcard_list.count()
        flashcard_dict['words_known'] = flashcard_list.filter(known=Yes).count()
        flashcard_dict['percent_known'] = int(float(flashcard_dict['words_known']) /    flashcard_dict['words_count'] * 100)
        flashcard_list.append(flashcard_dict)
    return render_to_response('report.html', { 'flashcard_list': flashcard_list })  

Answer 1

count requires an argument. It returns the number of instances of a particular item in a list.

>>> l = range(10) + range(10)
>>> l.count(5)
2

2 here is the number of 5s in the list. If you want the length of a list, use len.

>>> len(l)
20