I have a ListView listing a custom object (let's say MyObject
).
I want to filter it dynamically through an EditText
so I had to implement a getFilter()
with a publishResults method:
@Override protected void publishResults(CharSequence constraint, FilterResults results) { MyObjectAdapter.this.setItems((List<MyObject>) results.values); MyObjectAdapter.this.notifyDataSetChanged(); }
At this point, Eclipse complains: Type safety: Unchecked cast from Object to List<MyObject>
I am sure this cast will always be true, but Eclipse only suggests to add @SuppressWarnings("unchecked")
but I'm totally against SuppressWarnings
because it's only hiding the problem, not a solution...
I tried adding:
if(results.values instanceof List<MyObject>)
But Eclipse complains again, and this solves nothing...
Cannot perform instanceof check against parameterized type List<MyObject>. Use the form List<?>
I know the casting will always be correct, but which is the proper way to make the code to be sure results.values
is actually a List<MyObject>
?
Thanks in advance!
What Does the “unchecked cast” Warning Mean? The “unchecked cast” is a compile-time warning. Simply put, we'll see this warning when casting a raw type to a parameterized type without type checking. An example can explain it straightforwardly.
Unchecked cast means that you are (implicitly or explicitly) casting from a generic type to a nonqualified type or the other way around.
Unchecked assignment: 'java.util.List' to 'java.util.List<java.lang.String>' It means that you try to assign not type safe object to a type safe variable. If you are make sure that such assignment is type safe, you can disable the warning using @SuppressWarnings annotation, as in the following examples.
If all you have to work from is an Object
, then you can't check at runtime that you actually have a List<MyObject>
, because the generic type MyObject
is only used for compile-time type checking, it is not available at runtime. This is why you get an error when you try to add the instanceof
check.
If you are sure that your Object
really is always a List<MyObject>
then I'd say the @SuppressWarnings
is OK, if you document why you are sure it is not a problem.
If you absolutely want to avoid a warning though, you could create your own List
implementation (say, MyObjectList
) that is not itself generic but implements List<MyObject>
. Then you can do an instanceof
check against MyObjectList
at runtime.
Another option is to check for and cast to List<?>
as the instanceof
error suggests. Then you can iterate over the elements in the list and check if they are actually all instances of MyObject, and copy them to a new List<MyObject>
.
Well, I finally managed to find a solution.
Just as @Medo42 said:
Another option is to check for and cast to List as the instanceof error suggests. Then you can iterate over the elements in the list and check if they are actually all instances of MyObject, and copy them to a new List.
Even though I did not went through the process of creating a whole new object in order to make this particular case to work "warning-less" this was the right direction to go.
So I took @lokoko 's idea and use it in a new setItems()
method, with an Object
parameter instead of a List<MyObject>
in order to make sure
The result code is the following:
public void setItems(List<MyObject> var){ this.list = var; } public void setItems(Object var){ List<MyObject> result = new ArrayList<MyObject>(); if (var instanceof List){ for(int i = 0; i < ((List<?>)var).size(); i++){ Object item = ((List<?>) var).get(i); if(item instanceof MyObject){ result.add((MyObject) item); } } } setItems(result); }
Thanks everyone for your help!
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