Type for parameter in TypeScript Arrow Function

Question

With

"noImplicitAny": true

TypeScript will give the error:

Parameter 'x' implicitly has an 'any' type

for

.do(x => console.log(x));

and error

',' expected

for:

.do(x: any => console.log(x));

Answer 1

After some searching I found the correct way to define a type for the parameter is to add parentheses:

.do((x: any) => console.log(x));