two SQL COUNT() queries?

Question

I want to count both the total # of records in a table, and the total # of records that match certain conditions. I can do these with two separate queries:

SELECT COUNT(*) AS TotalCount FROM MyTable;
SELECT COUNT(*) AS QualifiedCount FROM MyTable
  {possible JOIN(s) as well e.g. JOIN MyOtherTable mot ON MyTable.id=mot.id} 
  WHERE {conditions};

Is there a way to combine these into one query so that I get two fields in one row?

SELECT {something} AS TotalCount, 
  {something else} AS QualifiedCount 
  FROM MyTable {possible JOIN(s)} WHERE {some conditions}

If not, I can issue two queries and wrap them in a transaction so they are consistent, but I was hoping to do it with one.

edit: I'm most concerned about atomicity; if there are two sub-SELECT statements needed that's OK as long as if there's an INSERT coming from somewhere it doesn't make the two responses inconsistent.

edit 2: The CASE answers are helpful but in my specific instance, the conditions may include a JOIN with another table (forgot to mention that in my original post, sorry) so I'm guessing that approach won't work.

Answer 1

One way is to join the table against itself:

select
   count(*) as TotalCount,
   count(s.id) as QualifiedCount
from
   MyTable a
left join
   MyTable s on s.id = a.id and {some conditions}

Another way is to use subqueries:

select
   (select count(*) from Mytable) as TotalCount,
   (select count(*) from Mytable where {some conditions}) as QualifiedCount

Or you can put the conditions in a case:

select
   count(*) as TotalCount,
   sum(case when {some conditions} then 1 else 0 end) as QualifiedCount
from
   MyTable

Related:

SQL Combining several SELECT results

Answer 2

In Oracle SQL Developer I had to add a * FROM in my select, or else i was getting a syntax error:

select * FROM 
    (select COUNT(*) as foo FROM TABLE1),
    (select COUNT(*) as boo FROM TABLE2);