Try-with-resources close order

Question

I am looking at examples of try-with-resources in Java and I understand the following one:

try (Connection conn = DriverManager.getConnection(url, user, pwd);
     Statement stmt = conn.createStatement();
     ResultSet rs = stmt.executeQuery(query);) {
  ...
}

So, the order of closing is:

rs.close();
stmt.close();
conn.close();

which is perfect because a connection has a statement and a statement has a result set.

However, in the following examples, the order of close I think it is the reverse of the expected:

Example 1:

try (FileReader fr = new FileReader(file);
     BufferedReader br = new BufferedReader(fr)) {
  ...
}

The order of closing is:

br.close();
fr.close();

Example 2:

try (FileOutputStream fos = new FileOutputStream("testSer.ser");
    ObjectOutputStream oos = new ObjectOutputStream(fs);) {
    ...
}

The order of closing is:

oos.close();
fos.close();

Are these examples correct? I think the close in those examples should be different because:

1. In the example 1 a BufferedReader has a FileReader.
2. In the example 2 an ObjectOutputStream has a FileOutputStream.

Answer 1

The ordering is the same: it's always the reverse of the order in which resources are specified. From JLS:

Resources are closed in the reverse order from that in which they were initialized.

However, if the later-specified resources themselves invoke the close() method of the earlier-specified resources (as is the case with BufferedReader and ObjectOutputStream), it may look like they are not happening in the expected order (and that close() will be invoked multiple times).