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I want to truncate the float values within the numpy array, for .e.g.
2.34341232 --> 2.34 I read the post truncate floating point but its for one float. I don't want to run a loop on the numpy array, it will be quite expensive. Is there any inbuilt method within numpy which can do this easily? I do need output as a float not string.
836
Use the int Function to Truncate a Float in Python The built-in int() function takes a float and converts it to an integer, thereby truncating a float value by removing its decimal places.
The numpy. trunc() is a mathematical function that returns the truncated value of the elements of array. The trunc of the scalar x is the nearest integer i which, closer to zero than x. This simply means that, the fractional part of the signed number x is discarded by this function.
Try out this modified version of numpy.trunc().
import numpy as np def trunc(values, decs=0): return np.trunc(values*10**decs)/(10**decs) Sadly, numpy.trunc function doesn't allow decimal truncation. Luckily, multiplying the argument and dividing it's result by a power of ten give the expected results.
vec = np.array([-4.79, -0.38, -0.001, 0.011, 0.4444, 2.34341232, 6.999]) trunc(vec, decs=2) which returns:
>>> array([-4.79, -0.38, -0. , 0.01, 0.44, 2.34, 6.99]) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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