Truncating decimal digits numpy array of floats

Question

I want to truncate the float values within the numpy array, for .e.g.

2.34341232 --> 2.34  

I read the post truncate floating point but its for one float. I don't want to run a loop on the numpy array, it will be quite expensive. Is there any inbuilt method within numpy which can do this easily? I do need output as a float not string.

Answer 1

Try out this modified version of numpy.trunc().

import numpy as np def trunc(values, decs=0):     return np.trunc(values*10**decs)/(10**decs) 

Sadly, numpy.trunc function doesn't allow decimal truncation. Luckily, multiplying the argument and dividing it's result by a power of ten give the expected results.

vec = np.array([-4.79, -0.38, -0.001, 0.011, 0.4444, 2.34341232, 6.999])  trunc(vec, decs=2) 

which returns:

>>> array([-4.79, -0.38, -0.  ,  0.01,  0.44,  2.34,  6.99])