I'm trying to solve the problem:
What is the value of the first triangle number to have over five hundred divisors?
A triangle number is a number in the sequence of the sum of numbers i.e. 1+2+3+4+5...
I'm pretty sure that this is working code but I don't know because my computer is taking too long to calculate it. Does anybody have any idea of how to make the program a little faster.
Thanks.
import math
def main():
l = []
one = 0
a = 1
b = 2
while one == 0:
a = a + b
b += 1
for x in range(1, int(a/2 + 1)):
if a % x == 0:
l.append(x)
if len(l) > 499:
print a
if __name__ == '__main__':
main()
Hints:
n
-th triangular number?n
and n+1
have no common factors (except 1
). Question: given number of factors in n
and n+1
how to calculate number of factors in n*(n+1)
? What about n/2
and (n+1)
(or n
and (n+1)/2
)?n
how to calculate number of divisors of n
?If you don't want to change your algorithm then you can make it faster by:
l.append
by factor_count += 1
int(a**.5)
instead of a/2
(use factor_count += 2
in this case). You'll have to think more and use less brute force to solve Project Euler questions.
In this case you should investigate which and how many divisors triangle numbers have. Start at the beginning, look for patterns, try to understand the problem.
You're not updating the value of one
, so your program will never end.
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