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I am using tomcat 6 and I have two webapps. One is webapp1 and the other one is webapp2. From a filter inside webapp2, I am trying to access the other webapp i.e webapp1. My Filter code is something like below
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
HttpServletRequest req = (HttpServletRequest)request;
System.out.println("requeted path = " + req.getRequestURI());
ServletContext othercontext = confg.getServletContext().getContext("/webapp1");
RequestDispatcher dispatcher = othercontext.getRequestDispatcher(req.getRequestURI());
dispatcher.forward(request, response);
chain.doFilter(request, response);
}
Any Idea what I am doing wrong ? I am always getting null as the othercontext value.
536
The default appBase location is "$CATALINA_BASE/webapps", or "$CATALINA_HOME/webapps", if no base directory has been defined. Next, if the application does not contain a Context fragment, one must be added within the appropriate Host element in Tomcat's server. xml configuration file.
public interface ServletContext. Defines a set of methods that a servlet uses to communicate with its servlet container, for example, to get the MIME type of a file, dispatch requests, or write to a log file. There is one context per "web application" per Java Virtual Machine.
Set crossContext = "true" in the server.xml. See the documentation for the context container.
Set to true if you want calls within this application to ServletContext.getContext() to successfully return a request dispatcher for other web applications running on this virtual host. Set to false (the default) in security conscious environments, to make getContext() always return null.
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