I am new to web-designing. I have this sample code which toggles a div when we click anywhere on the window.
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>slide demo</title>
<link rel="stylesheet" href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css">
<style>
#toggle {
width: 100px;
height: 100px;
background: #ccc;
}
</style>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"> </script>
</head>
<body>
<p>Click anywhere to toggle the box.</p>
<div id="toggle"></div>
<script>
$( document ).click(function() {
$( "#toggle" ).toggle( "slide" );
});
</script>
</body>
</html>
How can I add an image and change the image for show and hide? I have an '>' icon. When I click on it, div should appear and '>' should change to '<'
$('#buttonid').on('click', function () {
$('#toggle').toggle('slide');
});
add a button with an unique id like this
<button id="buttonid">click to toggle </button>
I think you can do as follow
<img src='source:<' id='imageid' data-othersource='source:>' />
You can declare an image like that with the two sources and then switch the src in jQuery.
//wait for the document to be fully loaded to execute
$(document).ready(function(){
//use event delegation
$(document).on('click','#imageid',function(){
var $this= $(this);
$('#toggle').toggle('slide',function(){
//swap src of the image on toggle is completed
var imgsrc = $this.attr('src');
$this.attr('src',$this.data('othersource'));
$this.data('othersource',imgsrc)
});
});
});
This way if for some reasons, you have to change the images, you don't need to get back to script, you just need to change the html.
http://jsfiddle.net/AmqcY/
Note: event delegation is not necessary in this case, but still i think it's important you read about that part for furthur use.
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