i have multiple forms with same class name
<form >
<input type="hidden" value="<%=ids%>" name="idd">
<input type="hidden" value="<%=email%>" name="cby">
<input type="text" class="cmd" name="cm" style="width:300px;" placeholder="comment">
<input type="submit" value="" style="display:none;">
</form>
<!-- n number of forms are generated using while loop-->
<form>
<input type="hidden" value="<%=ids%>" name="idd">
<input type="hidden" value="<%=email%>" name="cby">
<input type="text" class="cmd" name="cm" style="width:300px;" placeholder="comment">
<input type="submit" value="" style="display:none;">
</form>
Then how can i submit a single form among this n number of forms i tried using
$(function () {
$('form').on('submit', function (e) {
$.ajax({
type: 'post',
url: 'addfr.jsp',
data: $('form').serialize(),
success: function () {
location.reload();
}
});
e.preventDefault();
});
});
But it is submitting always 1st form among the n-forms. How can submit a random form among the n-forms. May any one help me please.
You need to reference the form with this
when you serialize it...
$(function () {
$('form').on('submit', function (e) {
$.ajax({
type: 'post',
url: 'addfr.jsp',
data: $(this).serialize(),
success: function () {
location.reload();
}
});
e.preventDefault();
});
});
Use this keyword. It will submit the form on which the event has been triggered.
why are u using location.reload?
$('form').on('submit', function (e) {
$.ajax({
type: 'post',
url: 'addfr.jsp',
data: $(this).serialize(),
success: function () {
location.reload();
}
});
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