I got the error for the below code
public static Moq.Mock<T> CreateInstanceOfIMock<T>() {
return new Moq.Mock<T>();
}
I have solved the error it by using referred class
type. See this below code
public static Moq.Mock<T> CreateInstanceOfIMock<T>() where T : class
{
return new Moq.Mock<T>();
}
Now I want to move this var mockColorsRepository = new Moq.Mock<IColorsRepository>();
code into common code by using generics
. here IColorsRepository
is an interface
. So I made an interface reference for T
instead of class
like this below code
public static Moq.Mock<T> CreateInstanceOfIMock<T>() where T : interface
{
return new Moq.Mock<T>();
}
But am getting The type T must be a reference type in order to use it as parameter
error. How can I refer interface
instead of class
to T
. How can I achieve this?
Interface Type Constraint You can constrain the generic type by interface, thereby allowing only classes that implement that interface or classes that inherit from classes that implement the interface as the type parameter.
In a generic type or method definition, a type parameter is a placeholder for a specific type that a client specifies when they create an instance of the generic type.
The where clause in a generic definition specifies constraints on the types that are used as arguments for type parameters in a generic type, method, delegate, or local function. Constraints can specify interfaces, base classes, or require a generic type to be a reference, value, or unmanaged type.
Value type constraint If we declare the generic class using the following code then we will get a compile-time error if we try to substitute a reference type for the type parameter.
class
and struct
in generic type constaints do not mean the same thing as the class
and struct
declarations that are used to declare class or struct types. Instead, they only restrict whether a generic type argument is a reference type (class
), or a value type (struct
).
So when you do where T : class
you are not saying that T
needs to be a class, you are saying that T
needs to be a reference type. Similarly struct
for value types.
Interfaces on their own do not have this property, so an interface can be implemented by both a reference type and a value type. As such, restricting your type to be of an interface does not really make sense there.
In your case, Moq requires you to pass a reference type, so you need to transitively carry over that type constraint in all your helper methods:
public static Moq.Mock<T> CreateInstanceOfIMock<T>()
where T : class
{
return new Moq.Mock<T>();
}
That’s all you need to do to create a mock of any valid type. You can use it with an interface using CreateInstanceOfIMock<IColorsRepository>()
or any other type.
Of course, at that point, the method does not really make that much sense since it does not give you any benefit over just instantiating the mock yourself.
There's no generic constraint in C# to enforce that a type argument is an interface. But where T : class
is really "where T
is a reference type" - it includes interfaces.
If you wanted to enforce that T
is an interface rather than a class, you could perform an execution-time check using typeof(T)
within the method, but in this case it sounds like you don't really need to constrain it to be an interface.
I'm not sure that the "helper" method is particularly useful though - if you compare:
var mock = Helper.CreateInstanceOfIMock<Foo>();
and
var mock = new Moq.Mock<Foo>();
or even (unless you have Mock<T>
as another type somewhere) just a using Moq;
directive and
var mock = new Mock<T>();
The latter seems just as readable and shorter... it makes sense if you're going to add more logic in your method, but if it's only ever going to call the constructor, I don't think I'd bother with it.
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