The simplest way to create a set of jquery object s

Question

Yeah, the way I was doing is

   A.add(B).add(C).add(D).show()

While A,B,C,D are jQuery objects. I wonder if there's such a simpler way to do this out there? I've tried all the following approaches, but no results:

$(A,B,C,D).show()
A.add(B,C,D).show()

All suggestions are welcome!

---

Addition to clarify the question:

The part ".show()" is just for demonstration. I just wanted to know how could I create a set of JQuery object like $('p') create a set of p tag.

In my real case, I used

$([A,B,C,D]).each(fn)

instead of .show() (And I wonder why this worked?) It's obviously that

$([A,B,C,D]).each(fn)
$('p').each(fn)

both work. But

$([A,B,C,D]).show()  //--doesn't work
$('p').show()        //--works

Just the second line works. Does anyone know the diffrence between them ? (I just thought they're the same, then made a bit of tangle in my question)

Answer 1

Assuming you have raw DOM elements (not jQuery objects such as $('#abc') or $('.abc')), there's no need to use add:

$([A,B,C,D]).show();

See the documentation of the $(...) function for details.

---

If you really want something like $(A,B,C,D) where A,B,C,D are jQuery objects, then the only real way is to roll your own function.

This does the trick:

var all = function() {
    var objs = $();
    $.each(arguments, function(i,e) {
        objs = objs.add(e);
    });
    return objs;
};

// ...

all(A,B,C,D).show();

Working example: http://jsfiddle.net/Jb6VD/5/