The same arithmetic operations give different results in C++ and Python

Question

I had to find the result of a function f(x) = x / (1-x)^2 , where 0 < x < 1. The value had to be formatted up to 6 decimal places only.

Here is my C++ code:

float x; scanf("%f",&x);
printf("%.6f",x/((1-x)*(1-x)));

And I did for the same in Python:

 x = float(input()) 
 print ("%.6f" % (x/((1-x)**2)))

For some values of x, both the programs give different answers.

For example, for x = 0.84567,

C++ gives 35.505867 and Python gives 35.505874

Why does this happen?
According to solution, the Python answers are right, while C++ answers are wrong.

Answer 1

#include <cstdio>
#include <cstdlib>
#include <iostream>
#include <iomanip>

int main()
{
    const char data[] = "0.84567";
    float x; 
    sscanf(data, "%f",&x);

    double x2;
    sscanf(data, "%lf",&x2);

    std::cout << std::setprecision(8) << (x/((1-x)*(1-x))) << std::endl;
    std::cout << std::setprecision(8) << (x2/((1-x2)*(1-x2))) << std::endl;
}

sample output:

35.505867
35.505874

Conclusion:

Python is using doubles, you're using floats.