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The relationship of overload and method return type in Java?

If there are two methods, they have different parameters, and their return types are different. Like this:

int test(int p) {
   System.out.println("version one");
   return p;
}

boolean test(boolean p, int q) {
   System.out.println("version two");
   return p;
}

If the return types are same, of course this is overload. But since the return types are different, can we regard this as overload still?

like image 680
wuyi Avatar asked Aug 08 '15 10:08

wuyi


2 Answers

To quote the official tutorial:

The Java programming language supports overloading methods, and Java can distinguish between methods with different method signatures. This means that methods within a class can have the same name if they have different parameter lists (there are some qualifications to this that will be discussed in the lesson titled "Interfaces and Inheritance").

Having a different return type is inconsequential to overloading. In fact, this is quite common with methods that return one of their arguments. E.g., java.util.Math has a bunch of overloaded max methods. A max of two ints return an int, a max of two doubles return a double, etc.

like image 194
Mureinik Avatar answered Sep 28 '22 12:09

Mureinik


consider following points for overloading:

  1. First and important rule to overload a method in java is to change method signature. Method signature is made of number of arguments, type of arguments and order of arguments if they are of different types.

    public class DemoClass {
        // Overloaded method
        public Integer sum(Integer a, Integer b) {
            return a + b;
        }
    
        // Overloading method
        public Integer sum(Float a, Integer b) {  //Valid
            return null;
        }
    }
    
  2. Return type of method is never part of method signature, so only changing the return type of method does not amount to method overloading.

    public class DemoClass {
        // Overloaded method
        public Integer sum(Integer a, Integer b) {
            return a + b;
        }
    
        // Overloading method
        public Float sum(Integer a, Integer b) {     //Not valid; Compile time error
            return null;
        }
    }
    
  3. Thrown exceptions from methods are also not considered when overloading a method. So your overloaded method throws the same exception, a different exception or it simply does no throw any exception; no effect at all on method loading.

    public class DemoClass {
        // Overloaded method
        public Integer sum(Integer a, Integer b) throws NullPointerException{
            return a + b;
        }
    
        // Overloading method
        public Integer sum(Integer a, Integer b) throws Exception{  //Not valid; Compile time error
            return null;
        }
    }
    
like image 29
Piyush Mittal Avatar answered Sep 28 '22 12:09

Piyush Mittal