Testing second condition when first false

Question

I have a simple program

temp='abc12a'
ver = 1
print(temp[-1].isdigit())
if temp[-1].isdigit() & int(temp[-1])!=ver:
    print(temp[:-1]+t)

which gives the output

False
Traceback (most recent call last):
  File "python", line 3, in <module>
  ValueError: invalid literal for int() with base 10: 'a'

Why does the second condition even get checked when the first is false? Is there a way to only do the second if the first is true that is cleaner than two ifs?

Answer 1

The & operator in Python checks as a bitwise and. It does not short circuit. The and operator properly short circuits, which is the behavior you are looking for.