Menu
I have a numpy one dimensional array c that is supposed to be filled with the contents of a + b. I'm first executing a + b on a device using PyOpenCL.
I want to quickly determine the correctness of the result array c in python using numpy slicing.
This is what I currently have
def python_kernel(a, b, c): temp = a + b if temp[:] != c[:]: print "Error" else: print "Success!" But I get the error:
ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
But it seems a.any or a.all will just determine whether the values aren't 0.
What should I do if I want to test if all of the scalers in the numpy array temp are equal to every value in the numpy array c?
691
Check if all elements are equal in a 1D Numpy Array using numpy. all() This confirms that all values in the array are the same.
You can convert the list to a set. A set cannot have duplicates. So if all the elements in the original list are identical, the set will have just one element. if len(set(input_list)) == 1: # input_list has all identical elements.
True if two arrays have the same shape and elements, False otherwise.
Comparing two NumPy arrays determines whether they are equivalent by checking if every element at each corresponding index is the same. Method 1: We generally use the == operator to compare two NumPy arrays to generate a new array object.
Why not just use numpy.array_equal(a1, a2)[docs] from NumPy's functions?
113
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
