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Trying to determine if my list of integer is made of odd or even numbers, my desired output is a list of true an/or false. Can I perform the following operation on the list lst or do I need to create a loop? A is the output.
List <int> lst = new List <int>(); A = IsOdd(lst); 
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Even numbers are divisible by 2. Odd numbers are not. for example 5%2 will return 1 which is NOT zero, (because 5 divided by 2 is 2 with a remainder of 1), therefore it is not even.
num = int (input (“Enter any number to test whether it is odd or even: “) if (num % 2) == 0: print (“The number is even”) else: print (“The provided number is odd”) Output: Enter any number to test whether it is odd or even: 887 887 is odd. The program above only accepts integers as input.
Now, to check whether num is even or odd, we calculate its remainder using % operator and check if it is divisible by 2 or not. For this, we use if...else statement in Java. If num is divisible by 2 , we print num is even. Else, we print num is odd.
One great way to use the modulus operator is to check if a number is even or odd. The modulus is perfect for this sort of test because any even number is, by definition, evenly divisible by 2. So any number that's divided by 2 with no remainder must be even.
You could try using Linq to project the list:
var output = lst.Select(x => x % 2 == 0).ToList(); This will return a new list of bools such that {1, 2, 3, 4, 5} will map to {false, true, false, true, false}.
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