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Is there a Boolean function to test whether an integer is an index value contained in a slice object without unpacking the start, stop, and step parameters?
3 in slice(1, 6, 2)
raises an error as slices are not iterable.
The predicate should work for arbitrary None, start, stop, step parameters. The logic is straightforward but hoping there's a built in or package.
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The Python "TypeError: slice indices must be integers or None or have an __index__ method" occurs when we use a non-integer value for slicing (e.g. a float ). To solve the error, make sure to use integers when slicing a list, string or any other sequence. Here is an example of how the error occurs.
The Python "TypeError: list indices must be integers or slices, not float" occurs when we use a floating-point number to access a list at a specific index. To solve the error, convert the float to an integer, e.g. my_list[int(my_float)] .
“Indexing” means referring to an element of an iterable by its position within the iterable. “Slicing” means getting a subset of elements from an iterable based on their indices.
The Python "TypeError: list indices must be integers or slices, not str" occurs when we use a string instead of an integer to access a list at a specific index. To solve the error, use the int() class to convert the string to an integer, e.g. my_list[int(my_str)] .
The logic is not as straightforward as you think, since it doesn't make sense to do this for a None stop or start (depending on the sign of step), since you need to specify a length.
Essentially, what you are asking for is containment in a range object, which holds the same information as a slice, but is a valid sequence, and supports fast containment checking. slice has a method called indices to help with the transformation, if you provide the length of the sequence you are interested in slicing:
def in_slice(n, s, length):
return n in range(*s.indices(length))
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