I have 2 range of numbers:
$startTime
to $endTime
$offerStartTime
to $offerEndTime
Each of the above variables are integers.
I want to see if the range offerStartTime
to offerEndTime
falls in the range startTime
and endTime
.
For example, if the startTime
and endTime
range was: 10 to 20, then the following example ranges would return true
:
offerStartTime: 5, offerEndTime: 11
offerStartTime: 5, offerEndTime: 100
offerStartTime: 10, offerEndTime: 15
offerStartTime: 10, offerEndTime: 100
offerStartTime: 12, offerEndTime: 15
offerStartTime: 19, offerEndTime: 100
The following would return false
:
offerStartTime: 1, offerEndTime: 3
offerStartTime: 90, offerEndTime: 100
offerStartTime: 1, offerEndTime: 10
offerStartTime: 20, offerEndTime: 100
How can I do this? Would ideally like answers in PHP, but pseudo code would be fine.
1) Sort all intervals in increasing order of start time. This step takes O(nLogn) time. 2) In the sorted array, if start time of an interval is less than end of previous interval, then there is an overlap.
The level to which pay ranges in adjacent grades in a category overlap. Pay Range.
data RESULTS; set EVENTS; OVERLAP = min(A2,B2) - max(A1,B1) + 1; if OVERLAP<0 then OVERLAP = 0; run; We can also zero out the negative values of variable x using max(0, x) expression that results in the following formula for the date ranges overlap calculation: Overlap = max(0, min(A2, B2) - max(A1, B1) + 1).
If you are just checking whether any part of the offer overlaps any part of the range, it's simple.
if ($offerStartTime < $endTime && $offerEndTime > $startTime) {
echo 'The ranges overlap';
}
Here's a picture representing all the possibilities of overlap and non-overlap to visualize why this works.
Based on your inputs and expected false outputs, I used <
and >
. If you wanted to also include ranges that intersected at a point, you would need to use <=
and >=
instead.
//$startTime to $endTime
//$offerStartTime to $offerEndTime
//you can compare php times by using normal comparators so this is just a logic problem. here's the solution.
//ok let's start by making sure that neither offered time is within the range because if it is we KNOW it's already good so
if(($offerStartTime < $endTime && offerStartTime > $startTime) || ($offerEndTime < $endTime && offerEndTime > $startTime)){
return true;
}
//so it's not easily already within the range so we have to test if the lower one is under the starting one but the other is above. ie.
elseif(($offerStartTime < $startTime) && ($offerEndTime > $startTime)){
return true;
}
//so the only other acceptable possibility is that the offered start time is lower than the endtime and the offered end time is higher ie
elseif(($offerStartTime < $endTime) && ($offerEndTime > $endTime)){
return true;
}
//so we've exhausted all other valid possibilities it must be false
else{
return false;
}
You can use range
and array_intersect
, i.e.:
function time_intersect($startTime, $endTime, $offerStartTime, $offerEndTime)
{
$start_to_end = range($startTime, $endTime, 1);
$offer_start_end = range($offerStartTime, $offerEndTime, 1);
if (!empty(array_intersect($start_to_end, $offer_start_end)))
{
# time overlaps
return true;
}
}
Explanation:
With range
we create 2 arrays
containing numbers based on the 4 variables (start, end), then we use array_intersect
to check if the 2 arrays have numbers in common, if the output is not empty, we know the numbers (time) overlap.
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