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Class Template Argument Deduction (CTAD) is a C++17 Core Language feature that reduces code verbosity. C++17's Standard Library also supports CTAD, so after upgrading your toolset, you can take advantage of this new feature when using STL types like std::pair and std::vector.
Which parameter is legal for non-type template? Explanation: The following are legal for non-type template parameters:integral or enumeration type, Pointer to object or pointer to function, Reference to object or reference to function, Pointer to member.
There are ways to restrict the types you can use inside a template you write by using specific typedefs inside your template. This will ensure that the compilation of the template specialisation for a type that does not include that particular typedef will fail, so you can selectively support/not support certain types.
Type inference or deduction refers to the automatic detection of the data type of an expression in a programming language. It is a feature present in some strongly statically typed languages. In C++, the auto keyword(added in C++ 11) is used for automatic type deduction.
I have below function (Just for reproducing the issue):
template <typename KeyT>
void func(const KeyT cptr) {
std::cout << typeid(KeyT).name() << std::endl;
}
I would like to call this with a string literal, like below:
func<char*>("literal");
But, I end up getting below warning:
warning: ISO C++11 does not allow conversion from string literal to 'char *' [-Wc++11-compat-deprecated-writable-strings]
I have a specific need to use char* as my Key type and I was expecting TAD to consider the param type as const char* in whole as I am not taking it by reference.
The warning comes with both clang and g++ compilers.
How is the param type being deduced here ?
Thanks in advance.
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