In a Python script, is there any way to tell if the interpreter is in interactive mode? This would be useful so that, for instance, when you run an interactive Python session and import a module, slightly different code is executed (for example, logging is turned off).
I've looked at tell whether python is in -i mode and tried the code there, however, that function only returns true if Python has been invoked with the -i flag and not when the command used to invoke interactive mode is python
with no arguments.
What I mean is something like this:
if __name__=="__main__": #do stuff elif __pythonIsInteractive__: #do other stuff else: exit()
There are two modes through which we can create and run Python scripts: interactive mode and script mode. The interactive mode involves running your codes directly on the Python shell which can be accessed from the terminal of the operating system.
Go to File -> New Window (Ctrl+N) and a window where you can write your program will pop up.
Step 1: Open the Python IDE and open the script file in Python IDE using the open option given. Or, we can even use the 'F5' button shortcut to run the script file in the Python IDE. That's how we can run or execute our Python script file using the Python IDE installed in our system.
Script Mode, is used when the user is working with more than one single code or a block of code. Interactive mode is used when an user wants to run one single line or one block of code. If one needs to write a long piece of Python code or if the Python script spans multiple files, interactive mode is not recommended.
__main__.__file__
doesn't exist in the interactive interpreter:
import __main__ as main print hasattr(main, '__file__')
This also goes for code run via python -c
, but not python -m
.
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